# Campbell Chapter 14 Gen Prob 1

Molecular Genetics: Problem 1
A man with hemophilia (a recessive , sex-linked condition has a daughter of normal phenotype. She marries a man who is normal for the trait. What is the probability that a daughter of this mating will be a hemophiliac? A son? If the couple has four sons, what is the probability that all four will be born with hemophilia?

Genotypes:

A man with hemophilia is XhY where h = hemophilia gene and H = the normal gene.
Any daughter with normal phenotype whose father has hemophilia will be a carrier.

Her genotype must be:

XhXH and NOT XHXH
We can use a Punnett square to show the probability of a daughter or son having hemophilia.

daughter x normal man
XhXH x XHY

A. If the daughter marries a normal male the probability of a daughter having hemophilia is zero.

B. About 50% of male children would have hemophilia (Boxes 2 and 4 above)

C. The probability that all 4 sons have inherited hemophilia would be: 1/2 x 1/2 x 1/2 x 1/2 or 1/16.

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